Tuesday, 29 November 2016

HOW TO CALCULATE CEMENT, SAND AND AGGREGATE QUANTITY IN CONCRETE

Consider Volume (Wet) = 1 m3
Grade of Concrete = M15 (Cement - 1 : sand - 2 : Aggregate - 4)
Sum Of Ratio = 1+2+4 = 7

Dry Volume = Wet Volume + 54% of Wet Volume = 1 + 0.54 = 1.54 m3

CEMENT
1. CUM : (1.54 x 1)/7 = 0.22 CUM
2. Kg : (1.54 x 1 x 1440)/7 = 316.8 Kg
3. Bags : We know 1 bag of cement weight = 50 Kg
                Then, 316.8 Kg contains, 316.8/50 = 6.336 bags
4. CFT : If we multiply No. of bags by 1.226 then we get the value in CFT.
               i.e, 6.336 x 1.226 = 7.77 CFT

SAND
1. CUM : (1.54 x 2)/7 = 0.44 CUM
2. Kg : (1.54 x 2 x 1450)/7 = 638 Kg [Density Varies in between 1450-1500 Kg/m3]
3. CFT : (1.54 x 2 x 35.3147)/7 = 15.54 CFT
     Alternative : No. of Cement Bags x Value of 1 bag of cement in CFT x ratio of sand
                       = 6.336 x 1.226 x 2 = 15.54 CFT

AGGREGATE
1. CUM : (1.54 x 4)/7 = 0.88 CUM
2. Kg : (1.54 x 4 x 1500)/7 = 1320 Kg [Density Varies in between 1450-1550 Kg/m3]
3. CFT : (1.54 x 4 x 35.3147)/7 = 31.07 CFT
     Alternative : No. of Cement Bags x Value of 1 bag of cement in CFT x ratio of sand
                       = 6.336 x 1.226 x 4 = 31.07 CFT


20 comments:

  1. how much Quantity of water ?

    ReplyDelete
  2. thank you , u r doing really good job sir

    ReplyDelete
  3. This comment has been removed by the author.

    ReplyDelete
  4. can ratio of dry water ratio change in other concret ratio means M25 etc

    ReplyDelete
  5. good work , keep going on it's very helpfull.

    ReplyDelete
  6. sir girder ka bbs bataye please..

    ReplyDelete
  7. sir;M35 ya kisi v design mix k nikalna ho to kse nikalnge

    ReplyDelete
  8. This comment has been removed by the author.

    ReplyDelete