Tuesday, 29 November 2016

DERIVATION : HOW MUCH CFT IN ONE BAG CEMENT

DERIVATION : HOW MUCH CFT IN ONE BAG CEMENT

We Know Density of Cement = 1440 Kg/m3

That means for 1 m3 Cement required is 1440 Kg
We Know, 1 Bag of Cement = 50 Kg
For,  1 m3 Cement required = 1440/50 = 28.8 Bags

We know, 1 m3 = 35.3147 CFT
or, 28.8 bags = 35.3147 CFT
or, 1 Bag = 35.3147/28.8 = 1.226 CFT

For more information please follow the link for the video BY LEARNING TECHNOLOGY:



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12 comments:

  1. Thanku sir you are doing great job wish you all the best god bless you

    ReplyDelete
  2. Thanku sir you are doing great job wish you all the best god bless you

    ReplyDelete
  3. Sir... Tomorrow I will going to be interview...And I read carefully & Completely your all the questions and answers..I like your Work...And it's good job....Wish you all the best ..God bless you....

    ReplyDelete
  4. Thank you sir. Great work for those who is bit confused. From Irshad Khan and sir why you minus half of bars from stirrups cutting length please explain.

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  5. Sir g please bata toh do ki aap soil CBR practical laboratory test upload Karwa sakte ho Ya nhi.... Sir koi problem nhi shayad aapki company mein cbr testing machine na ho, par bata toh de please.... Kamse kam main next question puchu apse.... Iam waiting

    ReplyDelete
    Replies
    1. Hello Vikas sir ji,
      Sorry mai reply nahi kar pa raha tha uske wajah se. CBR ka practical laboratory test mai av filhal nahi bata sakta kiu ki wo apparatus av hai nahi hamare saite pe. But ap youtube pe search kar sakte ho. waha pe hain.

      Delete
  6. Sir development lenght kaise calculate karte hain

    ReplyDelete
  7. Thank you sir.
    You are really great.
    God bless you.

    ReplyDelete
  8. Sir you are doing a good job.

    ReplyDelete